Mathematics
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OpenStudy (anonymous):
Find the remainder when f(x) = 2x^3 – 12x^2 + 11x + 2 is divided by x – 5.
is the answer 7? I'm not sure?
14 years ago
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OpenStudy (lgbasallote):
according to wolframalpha it's not
14 years ago
OpenStudy (lgbasallote):
you may have done something wrong in your division
14 years ago
OpenStudy (anonymous):
okay. I dnt know where I went wrong then...
14 years ago
OpenStudy (anonymous):
did u use synthetic division??? i would
14 years ago
OpenStudy (lgbasallote):
or i inputted something wrong in wolfram
14 years ago
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OpenStudy (lgbasallote):
im gonna do this by hand now..
14 years ago
OpenStudy (anonymous):
No I didn't use that method.
14 years ago
OpenStudy (anonymous):
–3
3
–7
14 years ago
OpenStudy (anonymous):
its all ways eaiser
14 years ago
OpenStudy (anonymous):
these are the rest of the answers.
14 years ago
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OpenStudy (anonymous):
what did you get on wolfalpha?
14 years ago
OpenStudy (lgbasallote):
wait..this software is so choosy lol
14 years ago
OpenStudy (anonymous):
i got -7
14 years ago
OpenStudy (lgbasallote):
lol i hate this software
14 years ago
OpenStudy (lgbasallote):
yeah i think it's -7
14 years ago
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OpenStudy (anonymous):
okay lol. and thank you katie.
14 years ago
OpenStudy (anonymous):
ur welcome!!
14 years ago
OpenStudy (lgbasallote):
moral: dont trust a software haha
14 years ago
OpenStudy (anonymous):
and yah it really is choosy so that's why I dnt use it.
14 years ago
OpenStudy (anonymous):
ikr :)
14 years ago
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OpenStudy (anonymous):
yeah i prefer free hand lol
14 years ago
OpenStudy (anonymous):
I'll try that one next time lol well thanks guys.
14 years ago
OpenStudy (anonymous):
\[f(x) = 2x^3 – 12x^2 + 11x + 2 \]\[f(5) = 2\times 5^3 – 12x\times 5^2 + 11\times5 + 2 \] is your remainder
14 years ago
OpenStudy (anonymous):
are you sure?
14 years ago
OpenStudy (anonymous):
\[f(5) = 2\times 5^3 – 12\times 5^2 + 11\times5 + 2\] typo there
14 years ago
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OpenStudy (lgbasallote):
@satellite73 remind me again how to use remainder theorem?
14 years ago
OpenStudy (anonymous):
very sure
14 years ago
OpenStudy (anonymous):
if you divide a polynomial \(p(x)\) by \(x-k\) your remainder is \(p(k)\)
14 years ago
OpenStudy (anonymous):
that's not any of my choices tho, so Idk.
14 years ago
OpenStudy (anonymous):
did you compute?
14 years ago
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OpenStudy (anonymous):
no, I re did it by hand.
14 years ago
OpenStudy (anonymous):
and I got -7 like they said.
14 years ago
OpenStudy (anonymous):
i get 7
14 years ago
OpenStudy (lgbasallote):
yup i got 7 too using remainder theorem
14 years ago
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OpenStudy (lgbasallote):
how'd you make wolframalpha work o.O
14 years ago
OpenStudy (anonymous):
ahhhh sorry
14 years ago
OpenStudy (anonymous):
i used the rong sign
14 years ago
OpenStudy (lgbasallote):
oh lol i made a syntax error in wolfram a while ago no wonder
14 years ago
OpenStudy (anonymous):
\[f(x)=2 x^3-12 x^2+11 x+2 = (1-2 x+2 x^2)×(x-5)+7\] and so it is pretty clear that \(f(5)=7\) because the second factor will be 0 leaving 7 as the answer
14 years ago