Question

g(n) = n^2 - 5n
h(n) = 2n + 1
Find g(y-2) - h(y-2)

I know how to do this problem, but I don't understand why the result is y^2-11y+17.
I get y^2-11y+11

First, when you plug in y-2 into g(y-2)=(y-2)^2-5(y-2), you get y^2-9y+14.

When you plug in y-2 into h(y-2)=2(y-2)+1, you get 2y-3

The question asks g(y-2)-h(y-2), so
y^2-9y+14 - 2y-3
I get y^2-11y+11, and that's wrong.

Answer 1

It should be y^2-11y+17 but I don't know how

Answer 2

The question asks g(y-2)-h(y-2), so
y^2-9y+14 - 2y+3=y^2-11y+17
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Answer 3

how did you get positive 3?

Answer 4

Ooh, so I distribute the minus sign in g(y-2) - h(y-2)?

Answer 5

yes

Answer 6

Thanks

Answer 7

ur welcome
and
\[\huge Welcome \ \ 2 \ \ Open \ \ Study\]

Answer 8

As we know that in function if we put any value in bracket then, we also have to put the value in the given expression. now it is given to us that \[g(n)=n^2-5n , h(n)=2n+1\] \[To find :-g(y-2)-h(y-2)\]
\[g(y-2)=(y-2)^2-5n , h(y-2)=2(y-2)+1\]
now, put this values of g(y-2) & h(y-2) as follows\[((y-2)^2-5n)-(2y-4-1)\] now, solve ths & get ur answer:)

Answer 9

Sorry, \[g(y-2)=(y-2)^2-5(y-2)\] so, u have to solve \[((y-2)^2-5(y-2)-(2y-4-1)\]