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Mathematics 21 Online
Parth (parthkohli):

Is anyone familiar with the Chinese Remainder Theorem? Can I be taught? Please don't give me any links, as they don't help much. Thank you for your help.

OpenStudy (hba):

u mean the k method remainder theorem

Parth (parthkohli):

I don't get your question, but using the Chinese Remainder Theorem, you may do questions like: \( \color{Black}{\Rightarrow x \equiv 4 (\mod{3}) }\) \( \color{Black}{\Rightarrow x \equiv 5(\mod{2})}\)

OpenStudy (hba):

m=3*2=6 a1=4 a2=5 .

OpenStudy (hba):

i am really sorry i dont remember it completely y1=1 y2=1

OpenStudy (hba):

m1=5 m2=4 i guess

OpenStudy (hba):

then u use a formula x=a1m1y1+a2m2y2+a3m3y3

OpenStudy (lgbasallote):

@hba the "k method" is just remainder theorem is it not? im imagining it to be when x - k is the divisor then p(k) is the remainder..idk...im not good with these fancy terms

Parth (parthkohli):

Wait. No. @lgbasallote The k method is the polynomial remainder theorem.

OpenStudy (hba):

yeah i understood what he meant when he wrote the question k method is diffrent

OpenStudy (hba):

this is the chinese one

OpenStudy (lgbasallote):

yes @hba and @ParthKohli i was just asking if k method = polynomial remainder theorem because i do not know these fancy terms

Parth (parthkohli):

I was not asking about the Polynomial Remainder Theorem. I was asking about the Chinese one.

Parth (parthkohli):

I was confused about how you should do it. I still am.

OpenStudy (hba):

but ive told u how to do it

OpenStudy (hba):

give me another question n ill show it to u again

OpenStudy (lgbasallote):

lol we know...like i said i was asking about k theorem if it's polynomial...and hbu already said the chinese thingy

Parth (parthkohli):

I am afk.. will call you guys later :P

OpenStudy (hba):

@lgbasallote yes the k theorem is the polynomial one

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