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a) Calculate the following (geometric) sums and series, respectively. ii) \(\Large \sum_{n=2}^{\infty}3^{1-n}\)
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a=1/3 q=1/3
can you do the complete solution pls, i have also some solution but i must be sure its correct, tomorrow i must give it up by mentor and its important
ok \[\huge \sum_{n=2}^{\infty} 3^{1-n}=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+... \]
yes i have the same one, can i give like that to by mentor ?
am i right?
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what you think is it possible to give like that to the mentor ?
no
what we need to add more ?
for geometric series like \[\large a+aq+aq^2+aq^3+...\] we have \[\huge s=\frac{a}{1-q}\]
hmm ...
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ook
u just recognize a and q
ok thanks
welcome
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