Question

Suppose you roll a six-sided die two times hoping to get two numbers whose sum is even. What is the sample space? How many favorable outcomes are there?

Answer 1

sample space = possible oucomes/total no of outcomes

Answer 2

sample space = 1/2 answer

Answer 3

ok so what will i divide by1/2

Answer 4

no its the answer

Answer 5

divide 6 by 12

Answer 6

assumptions, the die is fair. here is the sample space
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
then just take any pair adding to even eg 1+1 etc

Answer 7

total 6 even numbers divided by total 12

Answer 8

1) Here the experiement is - "A six-sided dice is thrown two times"

2) ==> The number of elements in sample space is = 36
[Since, in one throw there will be any six results as (1,2,3,4,5,6). Any one in the first can combine with any one in the second. Thus it is 6 x 6 = 36]

3) Hence the elements in the sample space = (1,1), (1,2), (1,3), (1,4), (1,5),1,6), (2,1) .... (2,6), (3,1), ..........(3,6), (4,1), ..... (4,6), (5,1), .... (5,6), (6,1) .... (6,6)

4) Required eventis: "Sum of the two numbers is even"

5) ==> Favourable is = [(1,1), (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3),(3,5), (4,2), (4,4), (4,6), (5,1), (5,3), (5,5), (6,2), (6,4) AND (6,6)}; thus number of elements = 18
Peejeshare.com gave a great example on how to solve this I post it above^^