Question

Vector Problem

So I set up the equation

Vector F_1 + Vector F_2 = Vector F_3

Then I calculated the magnitude of Vector F_3 to find the force exerted on the mule

using

|F_3| = (a^(2) + b^(2))^(1/2)

Doing this I acquired the answer 198N
at angle 66 degrees

For the Force needed to be exerted by a third person to make the force equal to zero

I simply made a negative version of vector F_3
acquired 198N at angle 114 degrees

according to the question this answer is incorrect (the correct answer being stated as d) what did I do wrong?

Answer 1

Can you show how you calculated \(F_{3}\) ? I am getting the magnitude of \(F_{3}= 185.4 N\)

Answer 2

F3 = [cos(60)120 + cos(75)80, sin(60)120 + sin(75)80]

Answer 3

Note that the x-component of \(F_{2}\) is negative

Other than that everything else seems fine.

Answer 4

oh yeah, thanks for pointing that out

Answer 5

|F_3|^2 = |F_1|^2 + |F_2|^2 - 2*|F_1|*|F_2|*\cos(\theta)
\tan(\phi) = \frac{|F_2|*\sin(\theta_2) + |F_1|*\sin(\theta_1)}{|F_2|*\cos(\theta_2)+|F_1|*\cos(theta_1)}
Find \theta + 180_\deg