Darren designed this triangular shaped entrance, ABC, to a mall. The height AD is 15 feet. Which expression can be used to find the distance between the points B and C of the entrance?
A.) \[15/\cos 65 degrees + 15/\cot 25 degreese\] B.) \[15 \cot 65 degreese + 15/ \cot25 degreese\] C.) \[15 (\cot 65 degreese +\sec 25 degreese)\] D.) \[15 (\cot 65 degreese + \cot25 degreese)\]
I'm pretty sure D is incorrect.
@myko or @SmoothMath could you help?
Okay, break this apart into two different problems. First, I'd like you to ignore the right side triangle, and just use the left side triangle to find out BD.
That part is just like the problem I helped you with earlier =)
so i have the 65 angle for that traigle.
i also know the height is 15
Yup. And can we look at the sides of the triangle and use a trig formula to make an equation?
yes, we could do cos65= 15/ adjacent?
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