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Mathematics 10 Online
OpenStudy (yanni):

simplify

OpenStudy (yanni):

\[\sqrt{50}+\sqrt{8}\]

OpenStudy (anonymous):

what times what times what = 50? what times what times what = 8? Example: \[\sqrt{12} = \sqrt{2*2*3} = \sqrt{2^{2}*3} = \sqrt{2^{2}}\sqrt{3} = 2\sqrt{3}\]

OpenStudy (yanni):

10 times 5 is 50 and 4 and 2 is 80

OpenStudy (anonymous):

what times what = 10 what times what = 4 You need to break the numbers down as much as possible.

OpenStudy (yanni):

2 times 5 is 10 and 2 times 2 =4

OpenStudy (anonymous):

Ok, therefore: \[\LARGE 50 = 2*2*5 = 2^{2}*5\] \[\LARGE 8 = 2*2*2 = 2^{2}*2\] \[\LARGE \sqrt{50}+\sqrt{8} = \sqrt{2^{2}*5}+\sqrt{2^{2}*2}\] From my example do you know what to do next? It may make it easier for you if you do it for one value at a time (square root of 50 for example)

OpenStudy (yanni):

20 *8= sqrt{160}

OpenStudy (anonymous):

No idea how you got that. Compare what I showed above with the square root of 12 against what we have so far for the square root of 50.

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