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find the indefinite integral
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\[\int\limits \sec^5(2x) \tan(2x)dx\]
u= sec(2 x) du= 2 sec(2 x) tan(2 x) dx \[ \int u^4 \frac {du}2 = \frac {u^5}{10} + C=\frac {\sec^5(2x)}{10}+C \]
eliassaab's answer is perfect, if you happen to have trouble with trigonometric identities you can also use the standard definitions of sec(x) and tan(x) to obtain the following integral: \[ \int \frac{sin(2x)}{cos^6{(2x)}} \] then I recommend an u-Substitution for cos(2x)
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