Question

a) Calculate the following (geometric) sums and series, respectively.
i) \(\Large \sum_{n=-2}^{10}2^{n}\)

Answer 1

i found 255,75 but i am suspected if its right

Answer 2

sorry i fount 1023.75

Answer 3

That's close, but I believe you are missing the \(2^{10}\) term.

Answer 4

because its starts from -2 i thought n should be 12

Answer 5

i used for first time maybe wolfram
its like that
http://www.wolframalpha.com/input/?i=sum+2^n%2C+n%3D-2+to+10

Answer 6

You would be adding \[2^{-2}+2^{-1}+2^{0}+...+2^{9}+2^{10}\]Which is exactly what the wolfram alpha link did for you.

Answer 7

\[\frac{8191}{4}\]

Answer 8

ok as a solution i can write this to my homework right?

Answer 9

That would work just fine.

Answer 10

ok thanks

Answer 11

you're welcome.