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evaluate the limit using l hospitals rule if needed
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\[\lim_{x \rightarrow \infty} \frac{5x^2+4x-8}{9x^2+9}\]
divide everything by x^2 in both the numerator and denominator
you'll be left with a rational answer + a series of zeros
hmm
that was clever heh
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GWAR! Wolfram makes nos ense :( http://www.wolframalpha.com/input/?i=limit+x+to+infinity+of+%285x%5E2%2B4x-8%29%2F%289x%5E2%2B9%29
@KonradZuse \[\large \frac{5 + \frac 4 x - \frac{8}{x^2}}{9 + \frac{9}{x^2}}\]
that's dividing by x^2
then what do we do from htere?
heh substitute infinity ;)
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sorry my head is ab out to explode I cannot think at all...
take x to infinity and beyond [note what happens to the fractions like 4/x]
remember \[\frac{a}{\infty} = 0\]
yuh
oic now :P
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ty
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