How to determine all values of p for which the integral is improper. integral dx/(x^2+2) -3 to p ?????????
is the integral (1/(x^2 +2))dx ?
true from -3 to p
and im assuming as p approaches infinity?
okay lets get on ahead with this you might be confused how do you even integrate this? or do you have any clue
\[\int_{-3}^p \frac{dx}{x^2 +2}dx\]
i assumed p approaches -infinite and +infinite~ i got -pi/2 and pi/2
lol too many dx
what was your integration?
\[\lim_{t \rightarrow p}\]\[[\tan^{-1} (x/\sqrt{2})]_{-3}^{t}\]
alright perfect good job first we will say as tan^(-1)(infinity) = pi/2 and tan^(-1)(- infinity) = -pi/2 so now let us see as p approaches infinity we have lim p --> inf = tan^(-1)( inf)/sqrt2 and therefore this is simply pi/2/sqrt 2 = pi/2sqrt2 and as lim p --> -inf = tan^(-1)( -inf)/sqrt2 and this is simply -pi/2/sqrt2 = -pi/2sqrt2 :) hope you followed
thx buddy~ got it~
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