After t years, the annual sales in hundreds of thousands of units of product q is given by q=(1/2)^(.8)^t 2) After how many years will the annual sales be about 95,350 units? Show your work. (Hint: You will have to take the log of both sides twice.)
\[q=\left(\frac12\right)^{.8^t}\] \[\log_{1/2}q=.8^t\] \[\log_{0.8}\left(\log_{1/2}\left(q\right)\right)=t\] \[t=\log_{0.8}\left(\log_{1/2}\left(95350\right)\right)\]
2,781 years?
\[t=\frac{\log_{10}\left(\frac{\log_{10}\left(95350\right)}{\log_{10}(1/2) }\right)}{\log_{10}(0.8)}\]
how sure are you?
how did you get to there?
which step didn't you follow/?
how you got to the new formula
take the log of both sides to base 1/2 take the log of both sides to base 0.8
i used the change of base formula in the last step so a calculator that only has base 10 could be used
hmm i keep getting error
for some reason im not getting a real answer either
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