Question

Integration of rational functions by partial fractions

Answer 1

answers

Answer 2

help

Answer 3

ok ......do you firstly know the method of partial fractions........??????

Answer 4

yes or no????

Answer 5

????

Answer 6

http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/partialfracdirectory/PartialFrac.html

Answer 7

\[
\frac{8 x^5-23 x^4-186 x^3+349
x^2+1034 x-1014}{(x-5)
(x-3) (x+3)^2}=\\8
x+\frac{2}{x-5}-\frac{4}{x-
3}-\frac{6}{x+3}+\frac{5}{(
x+3)^2}-7
\]

Answer 8

\[
\frac{9 x^3+25 x^2-159 x+265}{(x-4)^2
(x+7)^2}=\frac{6}{x+7}-\frac{4}{(x+7)^
2}+\frac{3}{x-4}+\frac{5}{(x-4)^2}
\]

Answer 9

It is easy to now integrate both.

Answer 10

i got stuck at finding A, B, C, and D.\[-8x^3-37x^2+80x-69 =A(x-5)(x+3)^2+B(x-3)(x+3)^2+C(x-3)(x-5)(x+3)+D(x-3)(x-5)\]