Question

integrate (from 1 to e^(37))
[pi.sin(pi.ln x)]/x

Answer 1

let
\[t=\pi \ln x\]

Answer 2

\[\int\limits_{1}^{e ^{37}} [\pi \sin (\pi \ln x)] \div x\]

Answer 3

try to sub it and tell me what u get

Answer 4

\[\Large \int _1^{3^{37}} \frac{\pi \sin (\pi \ln x)}{x} dx\]

Answer 5

?

Answer 6

e^37

Answer 7

lower limit corresponding to would be e^(1/pi)

Answer 8

lower limit will be pi ln(1)=0

Answer 9

aacha ok... and upper be 37 pi sin t dt

Answer 10

yes upper limit will be ..........37 pi

Answer 11

its 2 isnt it?

Answer 12

thats right

Answer 13

u did it well

Answer 14

you did it.. i cant believe i couldnt do such easy question in exam.. phew i have to keep a cool head.. -.-
anyways thanks =)

Answer 15

welcome

Answer 16

here another one.. tell me if i am right or wrong
if f: D->R such that f(x) =sqrt(sin(cosx)) + ln(-2cos^2(x) + 3 cos x -1) then
x1 to x2 integrate [cos(x) - 1/2] =?
where x1 and x2 belongs to D
and [.] is greatest integral part...

my answer comes out to be "0"