Question

If the system \[2x+3y-5=0,4x+ky-10=0\] has an infinite number of solutions then:

Answer 1

Ans. k=6

Answer 2

For Infinite number of solutions, one condition is there:

\[\huge \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \]

Use this concept..

Answer 3

Yes you are right jitesh, k = 6 is right answer..

Answer 4

But i wants the solution:)

Answer 5

Your question is firstly incomplete..
This Question says if these equations have Infinite Number of Solutions, then find the value of k...

Answer 6

ya! i don't see it

Answer 7

So, here we have to find k..
k = 6 is right..

Answer 8

i wants solution Plz

Answer 9

What solution??
I am not getting it..

Answer 10

if they have infinite number of solutions, then they are the same equation ... and differ by a scalar

Answer 11

How we found k??
You want that??

Answer 12

the solution of this question

Answer 13

2x+3y−5=0
4x+ky−10=0


2x+3y−5=0
2(2x+ky/2−5=0)

Answer 14

i only wants .how do u get it???

Answer 15

or

2x+3y−5=0
4x+ky−10=0

2(2x+3y−5=0)
4x+ky−10=0

4x+6y−10=0
4x+ky−10=0

Answer 16

k!

Answer 17

I have written the formula above..

Use that:

a1 = 2, b1 = 3
a2 = 4 and b2 = ??

Use that:

\[\large \color{green}{ \frac{2}{4} = \frac{3}{k} \implies 2k = 12 \implies k = 6}\]

Answer 18

waters method is fine too :)

Answer 19

k! i gt it:)
Thanx a lot @waterineyes & @amistre64

Answer 20

Welcome dear...

Answer 21

@zepp do you want to see more??
Ha ha ha..
Just kidding..

Answer 22

huh?

Answer 23

I personally prefer @amistre64's method ;P

Answer 24

Ha ha ha..