Question

Working with arithmetic sequences:

a1 = 11
last term = 151 = a?

What is the formula to figure out the last term?

Answer 1

you need to know the common difference..so ques incomplete as of now..

Answer 2

altough formulla for nth term :
a_n = a + (n-1)d
where a is first term
n is term no. n
a_n is nth term
and d is common difference..

Answer 3

Well the overall question I'm trying to answer is:
What is the 32nd term of the arithmetic sequence where a1 = 4 and a6 = 24 ?

I know how to find "d" using the formula for an arithmetic sequence, but since I do no know what exactly the nth term for 151 is in this case, I haven't been able to use the formula to get "d".

Answer 4

hey u need d u find it

Answer 5

So then how do I find d with the info that I have?

Answer 6

What is the 32nd term of the arithmetic sequence where a1 = 4 and a6 = 24 ?

\[a_6=a_1 + (6-1)d\]
\[24 = 4 + 5d\]
\[20=5d\]
\[d=4\]

Answer 7

Woops. posted the wrong question:

What is the sum of a 36-term arithmetic sequence where the first term is 11 and the last term is 151?

Answer 8

-.-

Answer 9

RIGHT THEREEE, needed that 36

Answer 10

a_n = 151
a_1 = 11
n = 36

can you find d?

Answer 11

d = 4

And staying up too long = stupidity

Answer 12

haha

Answer 13

yup, so you need to find the sum now?

"What is the sum of a 36-term arithmetic sequence where the first term is 11 and the last term is 151?"

Answer 14

S36 = 2916

Answer 15

I think I've learned more on here than on any of my eschool lessons.

Answer 16

haha thanks, kinda feel flattered.

and you got it right

Answer 17

Thanks for the help