Question:
The distance 'x' covered by a body moving in a straight line in time 't' is given by the relation $$2x^2+3x=t.$$If 'v' is the velocity of the body at a certain instant of time, its acceleration will be: - ?

Answer: --
$$\huge{-4v^3.}$$

Question

Question:
The distance 'x' covered by a body moving in a straight line in time 't' is given by the relation $$2x^2+3x=t.$$If 'v' is the velocity of the body at a certain instant of time, its acceleration will be: - ?

Answer: --
                 $$\huge{-4v^3.}$$

anonymous · Answer

$$2*2xv+3v=1, after  first  derivative  w.r.t   t$$
$$4(v ^{2}+ax)+3a=0$$ after second derivative 
simplify and you will have your answer i dont have much time someone else would do it. ..

experimentx · Answer

solve that quadratic equation for x to get explicit function of t time
differentiate it twice.

anonymous · Answer

take acceleration common take it on one hand side and put values of others at other side. . .

maheshmeghwal9 · Answer

ok gt it
thanx:)