Question

s=19t-4.9t^2

Answer 1

and what do you need to know? roots?

Answer 2

when a ball is thrown upward at aspeed of 19 m/s, its height s above the ground ( in meters) after t seconds is given by thefomula
Find the height of the ball after 3 seconds
I just need help setting the problem up pleas

Answer 3

Oh okay

Answer 4

Physics

\[s(t)=s_0 +v_0t + \frac{1}{2}at^2 \]
just in case you care for the background, so you see where the numbers come from, the gravitational force works against the path of motion, therefore it is
\[a=g=-9.81 \frac{m}{s^2} \]

So with the initial velocity of 19 m/s you obtain the following formula:

\[s(t)=19t-4.9t^2\]
This means the height s is a formula of time t and therefore you can only substitute the requested time into the formula and you will see what height your ball has at said time.

Answer 5

ok thank you