Question

1+n squared/ n squared - 1
simplify

Answer 1

is this the question?\[\frac{(1+n)^2}{n^2-1}\]

Answer 2

no its 1+ separate equation n squared over n square-1

Answer 3

so its this?\[\frac{1+n^2}{n^2-1}\]

Answer 4

no the one is kinda one over one

Answer 5

or this?\[1+\frac{n^2}{n^2-1}\]

Answer 6

This?:\[1+\frac{n^2}{n^2-1}=\frac{n^2-1}{n^2-1}+\frac{n^2}{n^2-1}\]

Answer 7

yes
to asnaseer

Answer 8

ok, so you could simplify as follows:\[1+\frac{n^2}{n^2-1}=1+\frac{n^2-1+1}{n^2-1}=1+\frac{n^2-1}{n^2-1}+\frac{1}{n^2-1}=1+1+\frac{1}{n^2-1}\]

Answer 9

thats confusing

Answer 10

which leads to:\[2+\frac{1}{n^2-1}\]

Answer 11

basically I added zero to the numerator by adding "-1+1"

Answer 12

no valpey is right the way because you find the lcd which is nsquared minus one

Answer 13

it all depends on what you mean by /simplify/

Answer 14

like find common denomenator and then you do it to the top to but then what i did was i got 2n squared minus one over nsquared minus one and i dont know what to do from there

Answer 15

I have given you my interpretation of simplify. I'm not sure how you have been taught to simplify by your teachers so I'm sorry but I cannot help out here.