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solve for x. 2[sqrt x+2]−3=7
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|dw:1341963500981:dw|
The first step is add 3 to both sides to go from \[\Large 2\sqrt{x+2} - 3 = 7\] to \[\Large 2\sqrt{x+2} - 3+3 = 7+3\] \[\Large 2\sqrt{x+2} + 0 = 10\] \[\Large 2\sqrt{x+2} = 10\]
Then what's next?
23
first get rid of single numbers, then square the square root and the other side since you are doing the opposite, then subtract the lonely 2
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10-2?
not quite, you divide both sides by 2 (to undo the multiplication of 2)
\[\Large \frac{2\sqrt{x+2}}{2} = \frac{10}{2}\] \[\Large \sqrt{x+2} = 5\]
wouldd that be the end result?
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