What is the volume of 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)? 10.7 L 22.4 L 47.0 L 82.0 L
use the relation PV=nRT. input STP values for temperature, pressure. Inout 2.1 moles for n, and use R from table with correct units. solve for V.
I am not good with any of this can you please explain step by step?
STP condition mean we have P=1 atm. T=273K. R=ideal gas constant, but make sure you use the one that has the same units of pressure, temperature that you are using. In this case R=0.0821 L*atm K^-1mol^1. You are provided with n=2.1 moles. \[V=\frac{nRT}{P}\]Input your values and solve.
There is a much easier way to get this answer though.
i am so confused.
at STP conditions, one mole of gas (any gas) occupies 22.4L of volume. Thus 2.1 moles of gas occupies approx 2.1*22.4=47.1 L
\[V=22.4n\]where n is the number of moles of gas at STP.
Both ways of getting the answer are equivalent.
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