Question

1) x to the negative 6th power over x to the negative 4th power
2) (y to the third power) to the negative 3rd power

Answer 1

1) use \[\huge \frac{a^m}{a^n} = a^{m-n}\]
2) use
\[\huge (a^m)^n = a^{mn}\]

Answer 2

is the first one one over x to the second power?

Answer 3

yup

Answer 4

\[ 1) \quad \frac{1}{x^2} \checkmark\]

Answer 5

kewl okay thanks is the second one one over y to the power of 6

Answer 6

nope

Answer 7

remember \[\huge (a^m)^n \implies a^{mn} \quad \textbf{NOT} \quad a^{m+n}\]

Answer 8

oh wait mistake...\[(^{y3})^{-2}\]

Answer 9

oh..now you're right

Answer 10

\[2) \quad \frac{1}{x^6} \checkmark\]

Answer 11

that's a y

Answer 12

yeah so number one and two are correct right?

Answer 13

yup

Answer 14

thank you

Answer 15

<tips hat>

Answer 16

uhm i also have another question x to the 7th pwer times x to the 5th power

Answer 17

(i'm checking my hmwk so yeah)