Use the properties of logarithms to write the following as sum and/or difference of logarithms: log√[(x^2 -1)/(x^3)((y^2+1)^5)]
ok i guess we can straighten out this mess
is the square root over the whole input, or just in the numerator
It's over the whole thing
the the first step is to get rid of the square root by putting a \(\frac{1}{2}\) out front
\[\frac{1}{2}\log\left(\frac{(x^2-1)}{x^3(y^2+1)^5}\right)\]
the turn the division in to a subtraction \[\frac{1}{2}\log(x^2-1)-\log(x^3(y+1)^5)\]
then turn the product in to a sum \[\frac{1}{2}\log(x^2-1)-\left(\log(x^3)+\log((y+1)^5)\right)\]
factor and pull out the exponents as multipliers [\frac{1}{2}\left(\log((x+1)(x-1))-3\log(x)-5\log(x+1)\right)\]
\[\frac{1}{2}\left(\log((x+1)(x-1))-3\log(x)-5\log(x+1)\right)\]
one last step \[\frac{1}{2}\left(\log((x+1)+\log(x-1)-3\log(x)-5\log(x+1)\right)\]
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