More Questions... Problems with Set Theory --Subset-- If every element of a set B is also a member of a set A, then we say B is a subset of A. We use the symbol ⊂ to mean “is a subset of” and the symbol ⊄ to mean “is not a subset of”. But there is a question in my textbook-----let A= {1,2, {3,4},5}. then which of the following statement are incorrect. (i) 1 ∈ A ii. ϕ ∈ A iii.{ϕ } ∈ A
3rd
@ganeshie8 incorrect are 1st and 2nd
sorry are 2nd and 3rd
i think 2nd and 3rd are incorrect 1st is true. A has the element 1 right
yes, it is true but why 2nd and 3rd are incorrect /
becos there is no "element" ϕ
ϕ ∈ A <------ this statement doesnt say "ϕ" is subset to A. it says the element "ϕ" belongs to A. which is incorrect
okay you mean phi isn't an element. so what it is? every set contains a phi
nope. every set doesnt contain the "element" phi every set contains an "empty set" phi
ϕ ⊂ A {} ⊂ A both above statements are same. empty set is represented using those symbols.
okay i got it
glad to hear ^_^
but this is right ϕ ∈ A ?
no sorry i just was a bit confused..
np :) thats not right becos it says the element ϕ belongs to A. we defined ϕ as a "subset" to every set. we didnt define ϕ as a "element" which belongs to every set.
@ganeshie8 but in my textbook it is given that ϕ ⊂ A it is right. but why?
thats right ϕ ⊂ A <---- says ϕ is a "subset" to every set
ϕ ∈ A <----- says ϕ is an "element" in every set
first one is true. second is false
"an empty set exists in every set " "an element ϕ doesnt exist in every set"
oh ganesh that you very much. greeting from india!
yw.. :))
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