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Mathematics 32 Online
OpenStudy (anonymous):

More Questions... Problems with Set Theory --Subset-- If every element of a set B is also a member of a set A, then we say B is a subset of A. We use the symbol ⊂ to mean “is a subset of” and the symbol ⊄ to mean “is not a subset of”. But there is a question in my textbook-----let A= {1,2, {3,4},5}. then which of the following statement are incorrect. (i) 1 ∈ A ii. ϕ ∈ A iii.{ϕ } ∈ A

ganeshie8 (ganeshie8):

3rd

OpenStudy (anonymous):

@ganeshie8 incorrect are 1st and 2nd

OpenStudy (anonymous):

sorry are 2nd and 3rd

ganeshie8 (ganeshie8):

i think 2nd and 3rd are incorrect 1st is true. A has the element 1 right

OpenStudy (anonymous):

yes, it is true but why 2nd and 3rd are incorrect /

ganeshie8 (ganeshie8):

becos there is no "element" ϕ

ganeshie8 (ganeshie8):

ϕ ∈ A <------ this statement doesnt say "ϕ" is subset to A. it says the element "ϕ" belongs to A. which is incorrect

OpenStudy (anonymous):

okay you mean phi isn't an element. so what it is? every set contains a phi

ganeshie8 (ganeshie8):

nope. every set doesnt contain the "element" phi every set contains an "empty set" phi

ganeshie8 (ganeshie8):

ϕ ⊂ A {} ⊂ A both above statements are same. empty set is represented using those symbols.

OpenStudy (anonymous):

okay i got it

ganeshie8 (ganeshie8):

glad to hear ^_^

OpenStudy (anonymous):

but this is right ϕ ∈ A ?

OpenStudy (anonymous):

no sorry i just was a bit confused..

ganeshie8 (ganeshie8):

np :) thats not right becos it says the element ϕ belongs to A. we defined ϕ as a "subset" to every set. we didnt define ϕ as a "element" which belongs to every set.

OpenStudy (anonymous):

@ganeshie8 but in my textbook it is given that ϕ ⊂ A it is right. but why?

ganeshie8 (ganeshie8):

thats right ϕ ⊂ A <---- says ϕ is a "subset" to every set

ganeshie8 (ganeshie8):

ϕ ∈ A <----- says ϕ is an "element" in every set

ganeshie8 (ganeshie8):

first one is true. second is false

ganeshie8 (ganeshie8):

"an empty set exists in every set " "an element ϕ doesnt exist in every set"

OpenStudy (anonymous):

oh ganesh that you very much. greeting from india!

ganeshie8 (ganeshie8):

yw.. :))

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