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OpenStudy (anonymous):

A complex question

OpenStudy (anonymous):

\[\left| z-1 \right|+\left| z+1 \right|=4\] Which turns into the messy \[\sqrt{(a-1)^2+b^2}+\sqrt{(a+1)^2+b^2}=4\] Which I have no idea about how to solve graphically.

OpenStudy (anonymous):

(Where z=a+ib)

OpenStudy (anonymous):

(And by 'graphically' I mean plotting the possible values of z on the complex plane)

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=sqrt%28%28x%2B1%29%5E2%2By%5E2%29%2Bsqrt%28%28x-1%29%5E2%2By%5E2%29%3D4 Can anyone explain why the graph is an ellipse?

OpenStudy (anonymous):

OK

OpenStudy (anonymous):

| a + bi - 1| + |a + bi + 1| = 4

OpenStudy (anonymous):

| (a -1) + (b)i | + | (a+1) + (b)i | = 4

OpenStudy (anonymous):

Now let me find the modulus which is given by sqrt( re(z)^2 + Im(z)^2)

OpenStudy (anonymous):

\[\sqrt{(a +1)^2 + b^2} + \sqrt{(a-1)^2 + b^2} = 4\]

OpenStudy (anonymous):

Then you should square both sides

OpenStudy (anonymous):

Actually that will be hard

OpenStudy (anonymous):

So move one of the square roots on the left then square both sides

OpenStudy (anonymous):

\[(\sqrt{(a+1)^2 + b^2} )^2= (4 - \sqrt{(a-1)^2 + b^2})^2\]

OpenStudy (anonymous):

Which will give you this

OpenStudy (anonymous):

There's still a horrible square root sign there, though.

OpenStudy (anonymous):

\[(a+1)^2 + b^2= 16 - 8\sqrt{(a-1)^2 + b^2} + (a-1)^2 + b^2\]

OpenStudy (anonymous):

I will get rid of it soon

OpenStudy (anonymous):

Ok now i am going to cancel some stuff and simplify this equation

OpenStudy (anonymous):

\[a^2 + 2a + 1 + b^2 = 16 - 8\sqrt{(a-1)^2 + b^2} + a^2 - 2a + 1 + b^2\]

OpenStudy (anonymous):

Now i can simplify further

OpenStudy (anonymous):

\[4a -16 = -8\sqrt{(a-1)^2+b^2}\]

OpenStudy (anonymous):

4a-16=-8sqrt(a^2-2a+1+b^2)

OpenStudy (anonymous):

Now I am going to square both sides again

OpenStudy (anonymous):

\[(4a -16)^2 = 64((a-1)^2 + b^2)\]

OpenStudy (anonymous):

Finally we have no more square roots

OpenStudy (anonymous):

Now i am going to expand

OpenStudy (anonymous):

\[16a^2 -128a + 256 = 64 a^2 -128a + 64 + 64b^2)\]

OpenStudy (anonymous):

it ends up as 192=48a^2+64b^2 I think

OpenStudy (anonymous):

Now simlify...

OpenStudy (anonymous):

SSo you get

OpenStudy (anonymous):

That actually agrees with the wolfram link I posted earlier. Thanks very much- I had little idea how to deal with square roots efficiently before!

OpenStudy (anonymous):

Final step: complete the square on a term

OpenStudy (anonymous):

oops

OpenStudy (anonymous):

Sorry yeah that was the answer 192 = 48a^2 +64b^2

OpenStudy (anonymous):

And thats an eclipse.

OpenStudy (anonymous):

No problem. =)

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