Question

\[\sqrt{x^2 + 4}\] Find the domain and range

Answer 1

Okay so, I feel... anyways...

That thing under the sqrt, 'x+4' has to equal or greater than '0' right??

Answer 2

sorry there is a change in question

Answer 3

\[\sqrt{x^2 + 4}\]

Answer 4

yeah that as well. x^2+4 should be greater than or equal to zero. so can you set up an inequality for this?

Answer 5

x^2 + 4 >= 0

x^2 > = -4

Answer 6

Domain = R becoz we can put any numbers

Answer 7

Exactly!

Answer 8

since there is sq term - ve will be + ve

Answer 9

so wat abt Range??

Answer 10

Range = [2 , infinity)

Answer 11

Now for the range - at x=0, is when the function attains its minimum value - what's that?

Answer 12

is that correct

Answer 13

Yeah, you're right with the range too!

Answer 14

thxx for helping!

Answer 15

No worries mate ;)