SIMPLE QUESTIONS FOR YOU ALL A bus was moving at a speed of 54 km/h. on applying brakes, it stopped in 8 seconds. calculate the speed acquired and distance traveled in this time.
The speed acquired is 0m/s
Speed acquired?????
Because the bus stopped
That be zero, since it stops!
plzzz do show u r solutions
distance use, x = v=0.5(u+v)t
give answer in one comment please its my request
So x = 0.5* 15 * 8 = 60m
Well, you have initial velocity = u = 54 kmph = 54 x (5/18) m/sec = 15 m/sec Final velocity = v = 0 Time = 8 seconds. Use Newton Unkle's equation # 1 ---> \( a = \frac{v-u}{t}\), and fond out the deceleration 'a'. Then, use \(v^2 - u^2 = 2as\) to find out the distance covered, i.e. 's'.
(Note of precaution: Newton's equations are only valid for uniform-linear motion, as you may know.)
sry... use \[x=\frac{v+u}{2} \times t\]
thanks aproov it proved my solution was wrong
where v is final speed=0 u is initial speed=15 and t=8
Yeah, using the average velocity funda is good actually, @King
oKAY thanks king to u as well
In fact innovative. :]
yw...thnx @apoorvk
lol
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