Question

Create your own third degree polynomial that when divided by x + 2 has a remainder of –4.

Answer 1

way easier than you think

Answer 2

take any second degree polynomial
make up your own, i will pick \(x^2+x+1\)
multiply it by \(x-2\) so i would get
\[(x-2)(x^2+x+1)\] then subtract 4, so i would get
\[(x-2)(x^2+x+1)-4\]

Answer 3

then you can see that if i divide the result by \(x-2\) the remainder will be \(-4\)
of course you still have to do some algebra
if you want to annoy your teacher, pick an even simpler second degree polynomial
simplest one i can think of is \(x^2\) so you could use
\[x^2(x-2)-4\]

Answer 4

@Tati_Lee is this clear? pick any second degree polynomial
multiply it by \(x-2\) ( do the algebra)
subtract 4
that is all

Answer 5

yea i get it thanks

Answer 6

i will help with the algebra if you need it, but you should try first, especially since you get to pick any second degree poly you like

Answer 7

sorry, but isn't it (x+2)?? because the zero is at +2

Answer 8

@ArturoBenedetti good call! it says divided by \(x+2\) not \(x-2\) i read it incorrectly

Answer 9

@Tati_Lee change all my \((x-2)\) to \((x+2)\) if would help if i could learn how to read

Answer 10

@satellite73 no problem

Answer 11

okay thank you both