Question

(-1, 3) and perpendicular to y = -1/3x + 7.

y = 3x - 12
y = 3x + 6
y = 3x - 6
y = 3x

Answer 1

what?

Answer 2

fine the equation of the line that passes through (-1, 3) and is perpendicular to y = -1/3x + 7. Is that your question?

Answer 3

yea ..

Answer 4

Need to find slope of y = -1/3x + 7 so we can determine the slope of the perpendicular line. We also note that two lines are perpendicular when the product of their slopes is equal to -1. To determine the slope, let's put the equation in slope-intercept form given as y=mx+b where m is the slope and b is the y-intercept when x=0 or at point(0,b).

slope m = -1/3, b = +7

therefore the slope of the perpendicular line is 3 because (-1/3)(3) = -1

So far, the equation of the perpendicular line is:

y = 3x + b

now just plug n the point give to find the value of "b"

3 = 3 + b
b = 0

the equation then is:

y = 3x + 0
y = 3x