Question

x squared minus 12 times x plus 20 all over x minus 10.

x − 2
x minus 2 all over x minus 10
x minus 2 all over 10
x minus 10 all over x minus 2

Answer 1

\[x^2-12x+\frac{20}{x-10}\]

Answer 2

so when you add those you get an answer?

Answer 3

or \[\large \frac{x^2-12x+20}{x-10}\]?

Answer 4

yes thats it thanks

Answer 5

Alright so you need to factor the numerator first, do you know how to do it?

Answer 6

At the numator we have \[\large x^2-12x+20\]and want this to be factored

Mushroom cheesecake, how do we do that?

Answer 7

It's in fact really simply, you'll need to find two number that's added up give the sum of the leading coefficient (the number sticked to \(x^2\)) and the last constant

Answer 8

and their sum gives the number stucked with x.

In our case
We need to find two numbers that summed gives 12 and multiplied gives 1 * 20 = 20

Answer 9

gives -12, sorry

Answer 10

These two numbers will be -2 and -10, by find 20's factors.

We can rewrite the numerator as \[\large x^2-12x+20=x^2-2x-10x+20\]

Answer 11

And that could be factored into
\[x(x-2)-10(x-2)=(x-10)(x-2)\]

Answer 12

Now we got \[\large \frac{(x-10)(x-2)}{(x-10)}=x-2\]

Answer 13

So A) would be the right answer.