Question

Can you check my work on this problem? ( i accidentally copied the wrong problem. The new one is at the end)

Answer 1

Is it 8 or is it no solution?

Answer 2

\[\sqrt{4x−7}−2=3\]you can always check solutions like this

if x =8 is a solution
\[\sqrt{4\times8−7}−2=3\]\[\sqrt{32−7}−2=3\]\[\sqrt{25}−2=3\]\[{5}−2=3\]\[3=3\]which is a true statement

Answer 3

so x=8 is a solution

Answer 4

But what is the solution set then? 8,3?

Answer 5

what would the equation become if x=3?

Answer 6

sqrt5-3 which is not 3. So how do i find the whole set? Or is it just eight?

Answer 7

Oops. Sorry guys but i messed up on the problem. Its actually \[\sqrt{4x-7}-1=2\] Not really sure how i messed that one up. Thats what i get for doing math this late at night.

Answer 8

\[\sqrt{4x-7}−1=2\]
add one to both sides
\[\sqrt{4x-7}=3\]square both sides
\[4x-7=9\]
\[4x=16\]
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