Two times of natural number is subtracted from its square and the result is 35.find the number.
A) 5
B) 7
C) 9
D) 6
E) 8
thats the right qst

Question

Two times of natural number is subtracted from its square and the result is 35.find the number.
A)	5
B)	7
C)	9
D)	6
E)	8
thats the right qst

anonymous · Answer

$$x^2 - 2x -35 = 0$$
$$(x-7)(x + 5)$$

x = 7

anonymous · Answer

x cannot be negative as it is a natural number so -5 is neglected..
x = 7..

apoorvk · Answer

Let the natural no. be 'x'
So it's square = $x^2$
2 times the no. = $2x$

Now, the square of the no. minus twice itself equals 35.
So,

$x^2 - 2x = 35$

So, can you solve this quadratic?

apoorvk · Answer

@shubham.bagrecha one slight error that you made - it would be "x^2 - 2x" and not "2x - x^2".

anonymous · Answer

Yeah he has done it wrong..

anonymous · Answer

let the natural no. be x.

2 times natural no . = 2x
square of no. = x^2

So, according to the condition
x^2 -2x  = 35
x^2 - 2x -35 =0
(x-7)(x+5)=0
so, x=7 and x=-5
x=-5 is not posssible as x is a natural no.