Question

\[\sqrt{48/75} * \sqrt{2}\]

Answer 1

ok so do you know that :
\[\sqrt{a}*\sqrt{b}=\sqrt{ab}\]

Answer 2

\[\sqrt{\frac {2*2*2*2*3}{5*5*3}}*\sqrt{2}\]
\[\frac {4}{5} \sqrt{\frac {3}{3}}*\sqrt{2}\]
\[\frac {4}{5}*1*\sqrt{2}\]

\[\frac {4}{5}\sqrt{2}\]

Answer 3

It was just a hint : can you solve further ?
May i know how u simplified it

Answer 4

@shubham.bagrecha please let the asker do it on herself ..

Answer 5

1.4142...

Answer 6

ok

Answer 7

no problem shubham .. it was just a request to u .. no problem

Answer 8

ok i will remember.

Answer 9

48 = 2 ^ 4 * 3. 75 = 3 * 5^2.

Use the property that mathslover mentioned above to combine that under one sqrt. also, sqrt(a/b) = sqrt(a) / sqrt(b). and sqrt(a^(2*b)) = sqrt( (a^b)^2 ) = a^b.

Answer 10

use those properties to solve the thing.

Answer 11

k..