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sec^2x dx/(secx+tanx)^2. integration from 0 to pi/2. Can someone please guide me to the answer
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Is it: \[\large \int\frac{sec^{2}xdx}{(secx+tanx)^{2}}\]?
@Mimi_x3 Couldn't understand you. What do you want to know?
Is that the integral? Just to make sure I don't want to do a integral which is not what you wrote.
yeah. that is the integral. Lower limit is 0 and upper limit is pi/2.
hm..would this work? \[\int\limits\frac{\sec^{2}xdx}{(\sin^{2}x+2sinx+1)\sec^{2}x} => \int\limits\frac{dx}{\sin^{2}x+2sinx+1} \]
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looks like a Weierstrass substitution http://en.wikipedia.org/wiki/Weierstrass_substitution
then how to solve the equation in the denominator??
Please solve this:|dw:1342104598564:dw|
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