Find f(x) and g(x) so the function can be expressed as y = f(g(x)). y =2/x^(2) + 3
please help :/
one way is that you take g(x)=x^2 and f(x)=2/x + 3. then y=f(g(x))= f(x^2)= y=2/x^2 + 3
how did you find out what f(x) was and g(x) was?...
it's a very easy technique. just take g(x) to be anything relating to the expression in the equation. for example, in this equation, you can take g(x) to be x^2, 1/x, 1/x^2, etc. Now, you have choose f(x) accordingly. if you take g(x)=x^2, then you have to take f(x)=2/x + 3; if you take g(x)=1/x, then you have to take f(x)=2x^2+3, and so on. Hope this helps.
but is that the answer to what f(x) and g(x) are?? or is that just a step to finding what they are...?
there are infinite no. of functions that can work as f and g. there is no one answer. for example, you take g(x)=2/x^(2) and f(x)=x+3; you can take g(x)=2/x^(2) + 1 and f(x)=x+2, g(x)=2/x^(2)+2 and f(x)=x+1... these all satisfy y=f(g(x)).
thanks so much!!!!! :D
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