Question

For which of the following functions is defined for all real numbers? (choices listed down below)

Answer 1

A) \[f(x) = \sqrt{3x-2}+ 3\]
B) \[f(x) =x^2-16\div x^2-25 \]
C) f(x) = \[1\div \sqrt[3]{x}\]
D) f(x) = x^1/2
E) f(x) = \[1\div x^2 +4\]

Answer 2

I wanna say e let me check

Answer 3

ok, and i thought so too. i just want to be sure. the problems above all look too complicated >.<

Answer 4

you'll get use to them :D

Answer 5

you would think by now i should be XD especially after all the math i have done lately XD

Answer 6

something new is always thrown at you :) dont worry

Answer 7

to be honest, i have no idea how to go about this problem... cant all of these be real numbers...? @_@

Answer 8

it means a domain of infinity

Answer 9

for all rreall numbers

Answer 10

the correct answer is d.

Answer 11

oh really? D: would you care to explain? i would love to know

Answer 12

it's not d at all x^1/2 is sqrt(x) -1 or any negative is not a real number

Answer 13

it is not D so don't fret about it.
you were correct with E

Answer 14

ooh unles she meant x^1/2 not x^(1/2) :P

Answer 15

oh thank goodness!! but i was still am confused as to why. i just guessed

Answer 16

for \(\frac{1}{x^2+4}\) you have to make sure the denominator is not zero
but \(x^2+4\geq 4\) for any \(x\) so it is never zero and therefore the domain would be all real numbers

Answer 17

1/2 is supposed to be a fraction as an exponent btw

Answer 18

oh wow, that makes much more sense. thanks a bunch satellite73!

Answer 19

btw when in exponent form put the fraction in parenthesis we humans know what you mean but not a computer :P

Answer 20

ah, alright. i need to make sure those technicalities are correct XD thank you too