determine whether the series is converges or diverges k=3 sigma k tends to infinity lnk/k

Question

anonymous · Answer

diverges for sure 
the denominator is a polynomial of degree 1, so even if the numerator was a constant this would not converge

anonymous · Answer

how...?

anonymous · Answer

if you like you can use the "comparison test" and compare it to $\sum\frac{1}{k}$

anonymous · Answer

plz explain now what u sayy...?

anonymous · Answer

hellow comporisn test..?

anonymous · Answer

how can i do comporisn can u explain ..

anonymous · Answer

the denominator in this case is $k$ and the numerator is $\ln(k)$ this is larger than the well known divergent harmonic series $\sum\frac{1}{k}$
since $\sum\frac{1}{K}$ diverges, and since $\frac{\ln(k)}{k}>\frac{1}{k}$ we know $\sum \frac{\ln(k)}{k}$ diverges as well

anonymous · Answer

why ln(k)/k >1/k