Question

need help!

Answer 1

\[x - 5\sqrt{x} +6=0\]

Answer 2

Like the last one, get 5sqrt(x) by itself on one side of the equation, and then square both sides.

Answer 3

wired is right :)

Answer 4

lol well so far i got \[x-6=5\sqrt{x}\]

Answer 5

and idk where to go from there

Answer 6

divide both sides by 5 :)

Answer 7

but i thought you had to square something or something like that

Answer 8

isolated for sqrt(x) you not there yet div by 5 first

Answer 9

You can do it either way actually. I find it simpler to square both sides at that point so you don't have to deal with fractions. Those fractions would cancel out later anyway, so no need to introduce them in the first place.

Answer 10

that is also true :)

Answer 11

\[(x-6)^{2} = (5\sqrt{x})^{2}\]

Answer 12

how do i do \[(5\sqrt{x})^2\]

Answer 13

well

(a*b) ^n is a^n*b^n right?

Answer 14

yes so the first is 25 and i still dont kno the second part

Answer 15

25*x :)

sqrt(x)^2 is x :)

Answer 16

oh lol im dumb lol

Answer 17

no you not :)

Answer 18

ha ha well i think so but thanks anyway :)

Answer 19

are not :P now finish the q :)

Answer 20

so i got\[x-36=25x\]

Answer 21

?????

Answer 22

that dont look right

Answer 23

oh wait i did it wrong sorry lol

Answer 24

x-36=25x???

Answer 25

(x−6)^2 is (x-6)*(x-6) use foil or whatever method you prefer.

Answer 26

my head hurts

Answer 27

Just as an FYI, here's another way to look at squaring a square root:
Note that:
\[\LARGE (X^{S})^{T} = X^{ST}\]
\[\LARGE \sqrt{x} = x^{1/2}\]
\[\LARGE (\sqrt{x})^{2} = (x^{1/2})^{2}=x^{(1/2)(2)} = x^{1}\]

Answer 28

does this thing have no solution!!??? lol cuz thts wat it seems like!

Answer 29

ohk thnk u

Answer 30

\[x-6=5\sqrt{x}\]
\[(x-6)^{2}=(5\sqrt{x})^{2}\]
\[(x-6)(x-6)=25x\]
\[x(x-6)-6(x-6)=25x\]

Answer 31

Do you see what to do now?

Answer 32

distribute?

Answer 33

Yep