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Which of the following correctly completes the square for the equation below? x^2+6x=5 A) (x+3)^2=5 B) (x+3)^2=14 C) (x+6)^2=5 D) (x+6)^2=14 Please help me...
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to complete the square you have to do this \[ \large x^2+6x+a=5+a \] now since \[ \large (y+z)^2=y^2+2yz+z^2 \] what is the value of a?
Is it one?
no! watch this \[ \large (x+k)^2=x^2+2xk+k^2 \] compare with what you have
To be honest I don't know what I'm doing.. like at all.
if you compare the last i wrote with what u have then \[ \large 6x=2kx \] then 6=2k then k=3 OK with this a=?
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