can someone please help & explain this question to me ? Which of the following are measurements of the sides of a right triangle? A.10,8,6 B.13,12,5 C.26,24,10 D.all of the above.
Do you know which property is satisfied by all right angled triangles?
like do you mean what all the angles add up to be ?
no - have you heard of the Pythagorus Theorem?
yes i have a^2+b^2=c^2 .
great! that is what you need to use here. in that equation, 'c' represents the hypotenuse of the triangle - which is the longest side. so what you need to do is to check which of the triples A, B, or C satisfy this equation.
so start with A, does this equation hold true?\[8^2+6^2=10^2\]
yes
good, now try the same check with the triples in B and C
oH ! okay so now i get it ! it wasnt so hard after all ! thanks a million ! (:
yw :)
BTW: what answer did you get?
i got answer 'A' ! b and c were really weird answers .
please double check your work - remember 'c' represents the longest side, so the equations you need to check are:\[12^2+5^2=13^2\]and:\[10^2+24^2=26^2\]
wait im confused right now .
in what part are you confused?
like im working out the equation and like no of them seem to work
ok, lets take the triples in B first, which were 12, 5 and 13 now what is \(12^2\)?
144
correct, and what is \(5^2\)?
25
correct again, so we get:\[12^2+5^2=144+25=169\]does this equal \(13^2\)?
yes it does
good, so now we know that both A and B satisfy the Pythagorus Theorem. now lets try the triples in C which were: 10, 24 and 26. what is \(10^2+24^2\)?
100
soo its all of them ?
yes :)
a time saving trick you can use with these triples is to first divide all the triples with any common factors that they may have
e.g. In A) 10, 8 and 6 can all be divided by 2, so we end up with: 5, 4 and 3 which means we just need to check if:\[3^2+4^2=5^2\]
ooo okay i will be sure to use that from now on ! now i really get it, i was using the wrong numbers the first time !
ok good - well done! :)
again THANK YOU !(:
again - yw :)
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