solve. then round answer to the nearest hundredth. 10^x+4=1000
@dpflan
Is it\[10^{x+4} = 1000\] In anyway case, it's just like the last one, you can solve this one in a minute ;)
yes..
10^x+4=1000 10^x = 996 x = log 996 2.9982
wait, if it's \[10^{x+4}\] then you need to re-solve
Otherwise, you got it
so if it is 10^x+4 its wrong?
No, you solved it correctly if the +4 is not in the exponent
be careful of what you're solving... which of these is the correct expression on the left: \[\large 10^{x+4} \] or \[\large 10^{x}+4 \]
the first one
then like @dpflan , said, you need to resolve... your original solution is for the second expression
10^(x + 4) = 1000 x + 4 = 3 x = -1
yeah, nice!
how would i round that to the nearest hundredth though?
?
Well, it currently have no fractional value, nothing passed the decimal point, so you can rewrite that \[-1=-1.00000....\]
thanks :)
No problem, thanks for the medal!
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