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Mathematics 7 Online
OpenStudy (anonymous):

how do you add fractions that have the variable x as their numerator?

OpenStudy (anonymous):

give an example

OpenStudy (anonymous):

Same way you add normal numbers......

OpenStudy (anonymous):

like x/2 + x/3-x/5-x/4

OpenStudy (lgbasallote):

you change them to common denominators first

OpenStudy (lgbasallote):

i.e. \[\frac{a}{3} + \frac{a}{2} \implies \frac{2a}{6} + \frac{3a}{6} \implies \frac{ 2a + 3a}{6} \implies \frac{5a}{6}\]

OpenStudy (anonymous):

\[x \div2+x ^{2}/3-x \div5-x ^{2}\div4\]

OpenStudy (lgbasallote):

is this your question: \[\LARGE \frac x2 + \frac{x^2}{3} - \frac x5 - \frac{x^2}{4}\]

OpenStudy (anonymous):

yah

OpenStudy (anonymous):

i don't know how to simplify it

OpenStudy (lgbasallote):

hmm....im trying to think the simplest way to explain LCM..

OpenStudy (anonymous):

(Half less a fifth) x plus (Third less a quarter) x^2 To start with

OpenStudy (anonymous):

thanks everyone, i understand it now.

OpenStudy (anonymous):

Find the LCM of the fractions. To do this you use prime factorization \[\frac{x}{2} +\frac{x^2}{3}-\frac{x}{5} -\frac{x^2}{4} \] Now what are the prime factors of 2,3,4,5 2 = 1*2 3= 1*3 4= 2*2 5 = 1*5 Those our the prime factors. Now find the LCM. 2*2*3*5 = 120 now times this by each fraction \[120(\frac{x}{2} +\frac{x^2}{3}-\frac{x}{5} -\frac{x^2}{4}) \] \[60x + 40x^2 - 24x - 30x^2\] Organize \[40x^2- 30x^2+60x - 24x \] Do the math \[10x^2+36x \]

OpenStudy (anonymous):

This is the best response so far, thank you :)

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