Evaluate the expression: sin 30 degrees cos 60 degrees + sin 60 degrees cos 30 degrees
Recall the double angle formula here, thus expression = sin (30 + 60) = sin90 = 1
okay
what about (cos 30 degrees)^2 - (sin30degrees)^2
Likewise double angle, cos(30+30)= cos(60) = 1/2
hmm my teacher never said anything about this double angle formula!!! ugh summer school. Thanks
this isnt double angle actually..
are you familiar with this @Lanik \[\large \sin (\alpha + \beta) = \sin \alpha \cos \beta + \sin \beta \cos \alpha\]
Oops typo my bad. The first case should have been compound angle formula.
yep better
i didnt notice the question changed lol
@Lanik if you're interested to "derive" the double angle formula.. \[\cos (\alpha + \beta) = \cos \alpha \cos \beta - \sin \alpha \sin \beta\] \[\text{If} \quad \alpha = \beta\] \[\cos (\alpha + \alpha) = \cos \alpha \cos \alpha - \sin \alpha \sin alpha\] \[\cos(2\alpha) = \cos^2 \alpha - \sin^2 \alpha\]
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