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Consider 0.10 M solutions of the following substances. Which would have the lowest pH? a.NaNO3 b.NH4NO3 c.NH4F d.NaF The answer is b ( NH4NO3), but I am not sure why? Can someone please explain to me how they reasoned this question?
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When B dissociates in water, it will form NH4+ cations and NO3- anions. NH4+ is a strong conjugate acid for NH3, which is a weak base, resulting in lowest pH It is not C as I don't think NH4F will fully dissociate in water... F is very electronegative.
Thanks :D....Do you mean D instead of F?
Nope, I meant F, which is fluorine in option C. NH4+ would be a stronger acid than Na+ in option D anyway, because Na+ cannot even donate a proton...
Okay I was just making sure....thanks again!!!
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