A box contains 9 red and 2 blue marbles. If you select one marble at random from the box determine the odds against selecting a red marble.
since there are 11 marbles in total, the odds are 9/11
ok is there any thing else to show how I could explain the answer
well the probability of picking a red marble depends on how many red marbles and the total number of marbles in the box. So if there are 9 red marbles out of 11 marbles, then there is a 9/11 chance of picking a red marble.
ok and thanks
Odds are not expressed the same as the actual probability of an event. \[ \quad \textbf{Probability} = \frac{\text{# desired outcomes}}{\text{# total poss. outcomes}} \\ ~\\ \quad \textbf{Odds} = \frac{\text{# desired outcomes}}{\text{# undesired outcomes}} \] So, when we refer to "the odds against selecting a red marble", we take the number of blue marbles over the number of red marbles.
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