Question

log(7) 1/343

Answer 1

-3

Answer 2

@jrzyby1 It is against the code of conduct of the site to just give answers ESPECIALLY with zero explanation.

Answer 3

\[\Large b^{y}=x\]
\[\Large \log_{b}{x}=y\]
\[\Large \log_{7}{\frac{1}{343}}=y\]
\[\Large 7^{y}=\frac{1}{343}=343^{-1}\]
\[\Large 7^{y}=343^{-1}\]
Solve.

Answer 4

\[\log_{7}{1 \over 343}=x \]can change it into exponential form as\[7^x=\frac{1}{343}\]& u can write it as\[7^x=343^{-1}\]\[7^x=(7^3)^{-1}\]now u know that if the bases are equal then powers are also equal so u can write the equation as\[x=3+(-1)\]\[x=2\]

Answer 5

Oopsie. Mistake here. ^

Answer 6

\( \color{Black}{\Rightarrow 7^{x} = 7^{-3}}\)

\( \color{Black}{\Rightarrow x = -3}\)

Answer 7

I think you confused \((7^3)^{-1}\) with \(7^3 \times 7^{-1}\)

Answer 8

i m sorry @ParthKohli . I was really confused