shown that the points A(-1,2),B(5,2) and C(2,5) are the vertices of an isosceles triangle find the area of ABC
I found the answer to AB,BC,and AC now can anyone tell me how to find the area
area = 1/2 * base*height
The answer to AB=6,BC=\/18,AC=\/18
It doesn't really matter what way you find the base or height
I know the formula to find the area how am i suppose to find the hieght?
find the midpoint of AB, call that D, then find the length of CD Area = CD x AB x 1/2
the midpoint is (2,2)
ok so I get the height 3
What the hell just happened?? I Answered my own question I found the answer..I'm a genius..lol Thanx for ya'll help
wait a sec
You found the 3 distances right?
yes
it says find the length perpendicular form a to bc
from*
No you don't need that much trouble for the area. Ever heard of Heron's Formula?
no...If its easier that way can you please explain it to me?
Ohkay, so if the lengths of the 3 sides of a triangle are a,b and c, then, semi-perimeter (half perimeter) = \(\large s = \frac{a+b+c}{2}\) Then, area 'A' of the triangle is: \[A = \sqrt{s(s-a)(s-b)(s-c)}\] (believe it's easier than it looks)
*believe me
and one more thing sometimes they ask you to find the length perpendicular ..like from A to BC
let me look at the formula for a moment
Ohkay if they have asked you to find the length of the perpendicular, then in this particular case, the perpendicular meets the opposite side at its mid-point (since this is an isosceles triangle)
what does "large s" and "frac" I know but just making sure
stand for*
Oh seems like the codes haven't processed, just refresh your tab once, that would make it alright.
ok
ok now their good I'm gonna look at em for a moment
I've pretty much got it but what does the "s" stand for?
s = (a+b+c)/2 simply this^. (called the semi-perimeter)
wow that pretty much solves the whole thing in a bit thanx again your incredible
ok so lets look at the perpendicular question what will i have to do if its not an isosceles triangle ?
Thanx for your Help I'm gonna go ahead and give my test bye
Hmm, that's difficult, let me think about ti and reply. All the best for your test man! :]
Thank you
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