What is the value of (g) at north pole and at equator .. Is their any way we can find their value ?

Question

mathslover · Answer

@Callisto

mathslover · Answer

can any1 help me ?

anonymous · Answer

Because the earth is very slightly flattened at the poles, so the North and South Poles are a bit closer to the center of the Earth than land on the Equator. And the South Pole is in Antarctica, which is a very high plateau, so the gravity there would be a bit less than that at the North Pole, which is in the middle of a deep ocean. The South Pole is colder than the North precisely because of this high elevation. 
g(at north pole)=GM/R^2=9.86m/s^2
g(at equator)= GM/R^2= 9.80m/s^2

anonymous · Answer

at North pole value of R = 6,356,800m
at equator value of R= 6,378,100m

anonymous · Answer

@annas your explanation is correct. Earth bulges slightly in the middle, hence the variation in g. but the values i got are 9.83 at poles and 9.78 at equator. the mean of which comes out to be 9.8 which we generally use.

anonymous · Answer

the values i get are round about which were mentioned in my book.

anonymous · Answer

and this is the reason we use 9.8m/s^2 generally

anonymous · Answer

two links which confirm the values 9.83 and 9.78. and i do recall learning these values in my lower classes. http://wiki.answers.com/Q/What_is_the_value_of_g_at_equator_and_poles http://www.goiit.com/posts/list/general-physics-what-is-value-of-g-at-poles-and-equator-and-1014572.htm;jsessionid=D1637134A44C074A24B021B665C0F818.node2#1250343

mathslover · Answer

Oh thanks a lot @annas and @Vaidehi09 
annas the value of R you got : if i didn't have this than i would not have been able to calculate that right ?

mathslover · Answer

@vishweshshrimali5 i want you to also enter here

anonymous · Answer

yes brother maths those values of R are necessary if you want to find values at poles and equator :) your welcome. i remember this because i got a question in my exams when i was in 10th grade.

mathslover · Answer

k thanks !! $$\huge{g_p>g_{eq.}}$$
p--> poles and eq-->equator

vishweshshrimali5 · Answer

@annas 
correct explanation

@mathslover 
Actually, this deviation of value of acceleration of gravity forces us to take an average value instead of the correct value.

Regarding your last reply,

This can be the answer of a question like

Why the gold measured at the equator increases its weight when brought to the poles ?

mathslover · Answer

Oh k ... thanks a lot @vishweshshrimali5 i got it perfectly now