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OpenStudy (anonymous):
Evaluate the integral. 0~3(6+6y-y^2)dy
a.-18
b.45
c.54
d.36
e.-12
13 years ago
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OpenStudy (mimi_x3):
\[ \int 6+6y-y^{2} dy\]?
13 years ago
OpenStudy (anonymous):
yupp with 0 at the bottom and 3 at the top
13 years ago
OpenStudy (mimi_x3):
Where are you having problems integrating?
13 years ago
OpenStudy (anonymous):
\[\large = \int\limits_{0}^{3}6.dy + \int\limits_{0}^{3}6y.dy - \int\limits_{0}^{3}y^2.dy\]
13 years ago
OpenStudy (anonymous):
the whole thing for this one i just need the answer because we already got them in class i just lost the paper and then we are supposed to do something with the answers
13 years ago
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OpenStudy (anonymous):
36
13 years ago
OpenStudy (anonymous):
I have more if you can help
13 years ago
OpenStudy (anonymous):
yep
13 years ago
OpenStudy (anonymous):
\[\int\limits_{-2}^{5}\left| 4x-x ^{2} \right|dx\]
13 years ago
OpenStudy (anonymous):
\[\int\limits_{0}^{1}3x ^{2}\cos(x ^{3})dx\]
13 years ago
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OpenStudy (anonymous):
do you know how to start the standard integrals?
13 years ago
OpenStudy (anonymous):
\[if \int\limits_{0}^{6} f(x)dx=10 and \int\limits_{0}^{4} f(x)dx= 7 find \int\limits_{4}^{6}f(x)dx\]
13 years ago
OpenStudy (anonymous):
yes
13 years ago
OpenStudy (anonymous):
ans is 3 for first one
13 years ago
OpenStudy (anonymous):
that isnt a choice
13 years ago
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OpenStudy (anonymous):
109, 123, 102, 209, 23
13 years ago
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